Question

chứng minh rằng 2003 mũ 2007 + 2007 mu 2003 chia het cho 10

Answer 1

Ta có: 2017+2017²⁰⁰³=2017+(..3)=(...0) (chia hết cho 10)

Do đó:2017+2017²⁰⁰³ chia hết cho 10

Answer 2

Ta có: 2003²⁰⁰⁷ + 2007²⁰⁰³

= 2003²⁰⁰⁴.2003³ + 2007²⁰⁰⁰.2007³

= (2003⁴)⁵⁰¹.(...7) + (2007⁴)⁵⁰⁰.(...3)

= (...1)⁵⁰¹.(...7) + (...1)⁵⁰⁰.(...3)

= (...1).(...7) + (...1).(...3)

= (...7) + (...3)

= ...0

Vì \(\overline{...0}⋮10\) nên \(2003^{2007}+2007^{2003}⋮10\)

Vậy...