Ta xet 3 truong hop
TH1 : x la so nguyen duong
Co 2x^8 + 2x^7 + 1 = duong + duong + duong = duong
Ma so duong luon lon hon 0
=> 2x^8 + 2x^7 + 1 > 0 voi x la so nguyen duong
TH2 : x la so nguyen am
Co 2x^8 + 2x^7 + 1 = duong + am + duong .
Do 2x^8 > 2x^7 nen tong tren mang dau duong
Ma so duong luon lon hon 0
=> 2x^8 + 2x^7 + 1 > 0 voi x la so nguyen am
TH3 : x = 0
Voi x = 0 ta co 2x^8 + 2x^7 + 1 = 0 + 0 + 1 = 1
Ma 1 > 0
=> 2x^8 + 2x^7 + 1 > 0 voi x = 0
Vay 2x^8 + 2x^7 + 1 > 0 voi moi x