Đặt A=\(1+3+3^2+3^3+...+3^{2018}\)
A=\(\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{2017}+3^{2018}\right)\)
A=\(4+3^2.\left(1+3\right)+...+3^{2017}.\left(1+3\right)\)
A=\(4+3^2.4+...+3^{2017}.4\)
A=\(4.\left(1+3^2+...+3^{2017}\right)\)
\(\Rightarrow\)A\(⋮\)4
Hok tốt nha!!!