`b` sai vì `0,5.(0,5)^2 = 0,125 = 1/8` chứ không bằng `1/4`
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Các câu hỏi tương tự
a)\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}-\dfrac{1}{6}-\dfrac{4}{35}\)
b)\(\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)-\left(5+\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(-6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
c)\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
Tính:
a) [\(\left(-2,7\right)^4\)]5 - [(-2,7)2 ] 10
b) (-0,5)5 : (-0,5)3 - \(\left(\dfrac{17}{2}\right)^7\) : \(\left(\dfrac{17}{2}\right)^6\)
c) (814 : 412) : (166 : 82)
Tìm x, biết:
a, -3/4 x - 3 = 1/4 x
b) 2,8 : 0,5 = \(|x-1|\): 1,5
c, x+2/ - 32 = -2/ x+2
d, 44-x / 3 = x - 12 / 5
Câu 13. (0,5 điểm): Tính giá trị $\left(2+\dfrac{1}{3}-0,4\right)-\left(7-\dfrac{3}{5}-\dfrac{4}{3}\right)-\left(\dfrac{1}{5}+\dfrac{5}{3}-4\right)$.
Tính bằng cách hợp lí giá trị của biểu thức.
A = \(\left(3-\dfrac{1}{4} +\dfrac{3}{2}\right)\)- \(\left(5+\dfrac{1}{3}-\dfrac{5}{6}\right)\)-\(\left(6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
B =\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)
a) 2\(\sqrt{16}\) + 8.(\(\dfrac{-1}{2}\) )\(^2\)
b) \(\dfrac{3}{4}\)-\(\dfrac{1}{4}\) .(3\(\dfrac{1}{2}\) - 0,5 + |\(\dfrac{-1}{2}\)|)
Bài 1.Tính hợp lý
a) \(\text{(0,5)}^3\) .\(2^3\)
b) \(\text{(0,25)}^2\).16
c) \(\left(\dfrac{3}{5}\right)^3:\left(\dfrac{-27}{1000}\right)\)
d) \(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
e) \(\dfrac{4^5.21+4^5.19}{2^{10}.11+2^{10}.5}\)
b. \(\dfrac{8^2.6^3}{9^2.16^2}\)
c. \(\dfrac{\left(0,15\right)^4}{\left(0,5\right)^5}\)
d. \(\left(\dfrac{3}{4}\right)^3\). \(\left(\dfrac{16}{9}\right)^3\)
TQ
24 tháng 5 2023 lúc 12:35
72x+72x+3=344 (5-x)(9x2-4)=0 \(\left|2-2x\right|\)-3,75=(-0,5)2
\(\sqrt{x-1}\)+\(\dfrac{2}{3}\)=1 (\(\dfrac{1}{3}\)-\(\dfrac{3}{2}\)x)2=2\(\dfrac{1}{4}\) giúp mình với!!!! cảm ơn nhìu=))❤