Ta có: \(\frac{3a+5b}{2a-b}=\frac{3c+5d}{2c-d}\)
=> (3a+5b)(2c-d) =(2a-b)(3c+5d)
=> 3a(2c-d) +5b(2c-d) =2a(3c+5d) -b(3c+5d)
=> 6ac -3ad +10bc -5bd =6ac +10ad -3bc -5bd
=>7bc=7ad
=> bc=ad
=> a/b =c/d
Ta có: \(\frac{3a+5b}{2a-b}=\frac{3c+5d}{2c-d}\)
=> (3a+5b)(2c-d) =(2a-b)(3c+5d)
=> 3a(2c-d) +5b(2c-d) =2a(3c+5d) -b(3c+5d)
=> 6ac -3ad +10bc -5bd =6ac +10ad -3bc -5bd
=>7bc=7ad
=> bc=ad
=> a/b =c/d
Cho\(\frac{3a+5b}{2a-b}=\frac{3c+5d}{2c-d}CMR\frac{a}{b}=\frac{c}{d}\)
cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\).chứng minh
a)\(\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
b) \(\frac{2a+3b}{2a-3b}\)=\(\frac{2c+3d}{2c-3d}\)
cho a,b,c,d ≠0 và a b = c d CMR \(\frac{2a-5b}{3a}=\frac{2c-5d}{3c}\)
các bn giúp mk vs
cho \(\frac{a}{b}=\frac{c}{d}cmr\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
Cho a, b, c, d khac 0 và \(\frac{a}{b}=\frac{c}{d}\). Hãy chưng minh \(\frac{2a-5b}{3a}=\frac{2c-5d}{3c}\)
cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh rằng \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
cho tỉ lệ thức\(\frac{a}{b}=\frac{c}{d}\).chứng minh
a) \(\frac{3a+5b}{3a-5b}=\frac{3c+5b}{3c-5b}\)
b)\(\frac{2a+3b}{2a-3b}=\frac{2c+3d}{2c-3d}\)