Đkxđ : \(x+y\ne0\)
\(x^2-2y^2=xy\Rightarrow x^2-y^2=xy+y^2\)
\(\Rightarrow\left(x-y\right)\left(x+y\right)=y\left(x+y\right)\)
\(\Rightarrow x-y=y\)
\(\Rightarrow x=2y\)
Thay x = 2y vào M có :
\(M=\frac{2y-y}{2y+y}=\frac{y}{3y}=\frac{1}{3}\)
Vậy ...
cho x+y =1 . tinh gia tri cua bieu thuc A=x^3+y^3+3xy
chox-y=1. tinh gia tri cua bieu thuc B=x^3-y^3-3xy
cho x+y=1 . tinh gia tri cua bieu thuc C=x^3+y^3+3xy(x^2+y^2)+6x^2*y^2(x+y)
cho x,y khac nhau biet x2-y=y2-x. tinh gia tri cua bieu thuc A=x2+2xy+y2-3x-3y
Cho x+y=2, tinh gia tri cua bieu thuc:
M=3(x^2+y^2)-(x^3+y^3)+1
Bai 2:Cho a+b=5,tinh gia tri bieu thuc:
M=3a^2-2a+3b^2-2b+6ab+100
1. cho x+y=7 va xy=8 gia tri cua bieu thuc x3+y3 = ?
2. gia tri lon nhat cua bieu thuc B= 1+3x-x2 la ?
1. cho x+y=7 va xy=8 gia tri cua bieu thuc x3+y3 = ?
2. gia tri lon nhat cua bieu thuc B= 1+3x-x2 la ?
Tinh gia tri cua bieu thuc A=x-2009/2009x+y
Biet x^2-2y^2=xy( voi 2009x+y khac 0 )
cho\(x
1. biết x2-2y2=xy,y\(\ne\)0,x+y\(\ne\)0. thì gia tri cua bieu thuc Q=\(\frac{x+y}{x-y}\)=
2.cho x\(\ne\)0,y\(\ne\)0 thoa man x+y=4 ;xy=2 .gia tri cua bieu thuc A=\(\frac{1}{x^3}+\frac{1}{y^3}\)la
3.gia tri cua bieu thuc A=\(\frac{81^8-1}{\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}\)la
tinh gia tri cua bieu thuc :x*y voix+y=2
