Ta có:
\(\frac{x}{2}=\frac{y}{3}\)
\(\Leftrightarrow3x=2y\)
\(\Leftrightarrow y=1,5x\left(1\right)\)
Do \(x^2.y^2=576\)
\(\Leftrightarrow x.y=\sqrt{576}=24\left(2\right)\)
Thay \(\left(1\right)\) và \(\left(2\right)\)
\(\Leftrightarrow x.1,5x=24\)
\(\Leftrightarrow x^2=\frac{24}{1,5}=16\)
\(\Leftrightarrow x^2=16\Leftrightarrow x=\sqrt{16}=4\)
\(\Leftrightarrow y=1,5.4=6\)
\(\Leftrightarrow x-y=4-6=-2\)
Vậy \(x-y=-2\)