Question

Cho tam giác ABC. Gọi M, N, P lần lượt là trung điểm của các cạnh AB, BC, CD. CMR:

a. \(\overrightarrow{AM}+\overrightarrow{BN}=\dfrac{1}{2}\overrightarrow{AC}\)

b. \(\overrightarrow{AM}+\overrightarrow{BN}+\overrightarrow{AP}+\overrightarrow{BM}=\overrightarrow{MC}\)

c.\(\overrightarrow{AM}+\overrightarrow{BN}+\overrightarrow{CP}=\overrightarrow{0}\)

d. \(\overrightarrow{OA}+\overrightarrow{OB}+\overrightarrow{OC}=\overrightarrow{OM}+\overrightarrow{ON}+\overrightarrow{OP},\forall0\)

Answer 1

a: \(\overrightarrow{AM}+\overrightarrow{BN}=\dfrac{1}{2}\overrightarrow{AB}+\dfrac{1}{2}\overrightarrow{BC}=\dfrac{1}{2}\overrightarrow{AC}\)

b: \(=\dfrac{1}{2}\overrightarrow{AC}+\dfrac{1}{2}\overrightarrow{AC}+\dfrac{1}{2}\overrightarrow{BA}\)

\(=\overrightarrow{AC}+\dfrac{1}{2}\overrightarrow{BA}\)

c: \(\overrightarrow{AM}+\overrightarrow{BN}+\overrightarrow{CP}\)

\(=\dfrac{1}{2}\overrightarrow{AB}+\dfrac{1}{2}\overrightarrow{BC}+\dfrac{1}{2}\overrightarrow{CA}\)

\(=\dfrac{1}{2}\left(\overrightarrow{AC}+\overrightarrow{CA}\right)=\overrightarrow{0}\)