Sửa lại đề nha:
\(S=\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}\)
Ta có:
\(S=\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}>\frac{3}{14}+\frac{3}{14}+\frac{3}{14}+\frac{3}{14}+\frac{3}{14}=\frac{15}{14}>1\left(1\right)\)
Lại có:
\(S=\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}< \frac{3}{10}+\frac{3}{10}+\frac{3}{10}+\frac{3}{10}+\frac{3}{10}=\frac{15}{10}< \frac{20}{10}\left(2\right)\)
Từ (1) và (2) \(\Rightarrow1< S< 2\left(đpcm\right)\)
Chúc em học tốt!
S=3/10+3/11+3/12+3/13+3/14 > 3/14+3/14+3/14+3/14+3/14=15/14>1
=>3/10+3/11+3/12+3/13+3/14>1=>S>1
S=3/10+3/11+3/12+3/13+3/14 < 3/11+3/11+3/11+3/11+3/11=15/11<2
=>3/10+3/11+3/12+3/13+3/14<2=>S<2