\(\frac{1}{11}\)> \(\frac{1}{20}\)
\(\frac{1}{12}\)> \(\frac{1}{20}\)
.
.
.
\(\frac{1}{19}\)>\(\frac{1}{20}\)
\(\frac{1}{20}\)= \(\frac{1}{20}\)
=> S = 1/11+1/12+...+1/20>1/20+1/20+1/20+1/20+1/20+1/20+1/20+1/20+1/20+1/20=10*1/20=1/2 (đpcm)
Ta có:
\(\frac{1}{11}>\frac{1}{20}\)
\(\frac{1}{12}>\frac{1}{20}\)
.............
\(\frac{1}{20}=\frac{1}{20}\)
\(\Rightarrow\frac{1}{11}+\frac{1}{12}+...+\frac{1}{20}>\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}\) ( 10 phân số \(\frac{1}{20}\))
\(\Leftrightarrow\frac{10.1}{20}=\frac{10}{20}=\frac{1}{2}\)
Vì \(\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}=\frac{1}{2}\). Mà \(\frac{1}{11}+\frac{1}{12}+...+\frac{1}{20}>\frac{1}{20}\Rightarrow\frac{1}{11}+\frac{1}{12}+...+\frac{1}{20}>\frac{1}{2}\)