Question

Cho P(x) = 2x^3 +3x^2 -11x +10

Q(x)= 2x^3 - 4x^2 - 2x + 4

Tìm x sao cho P(x)-Q(x)= 2x^2 - 3x + 6

Answer 1

\(P\left(x\right)-Q\left(x\right)=7x^2-9x+6\)

Để TMĐK đề bài thì: \(7x^2-9x+6=2x^2-3x+6\)

\(\Leftrightarrow5x^2-6x=0\Leftrightarrow x\left(5x-6\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{6}{5}\end{cases}}\)