\(\Delta=m^2+8m+16-4m^2-8m+4=20-3m^2\ge0\Leftrightarrow-\sqrt{\frac{20}{3}}\le m\le\sqrt{\frac{20}{3}}\)
\(2.x_0=m+4+\sqrt{20-3m^2}\ge-\sqrt{\frac{20}{3}}+4\Leftrightarrow Minx_0=\frac{-\sqrt{\frac{20}{3}}+4}{2}=2-\sqrt{\frac{5}{3}}\)
\(2.x_0=m+4-\sqrt{20-3m^2}\le\sqrt{\frac{20}{3}}+4\Leftrightarrow Maxx_0=\frac{\sqrt{\frac{20}{3}}+4}{2}=2+\sqrt{\frac{5}{3}}\)