Câu 1:
Gọi đơn chất halogen là X2
\(Cu+X_2\underrightarrow{^{to}}CuX_2\)
Ta có:
\(n_X=\frac{5,6}{22,4}=0,25\left(mol\right)=n_{CuX2}\)
\(\Rightarrow M_{CuX2}=64+2X=\frac{33,75}{0,25}=135\)
\(\Rightarrow X=35,5\left(Clo\right)\)
Halogen là Cl2 - Clo
Câu 2:
\(PTHH:Fe+2HCl\rightarrow FeCl_2+H_2\)
_______0,15__0,3___0,15___0,15__
\(n_{Fe}=\frac{8,4}{56}=0,15\left(mol\right)\)
a,\(V_{H2}=0,15.22,4=3,36\left(l\right)\)
b, \(CM_{HCl}=\frac{0,3}{0,2}=1,5M\)
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