Vì a//b nên \(\widehat{C_1}+\widehat{D_1}=180^0\left(trong.cùng.phía\right)\)
Mà \(\widehat{C_1}-\widehat{D_1}=30^0\)
\(\Rightarrow\left\{{}\begin{matrix}\widehat{C_1}=\left(180^0+30^0\right):2=105^0\\\widehat{D_1}=180^0-105^0=75^0\end{matrix}\right.\)
Vì a//b nên \(\left\{{}\begin{matrix}\widehat{C_1}=\widehat{D_2}=105^0\\\widehat{D_1}=\widehat{C_2}=75^0\end{matrix}\right.\left(so.le.trong\right)\)