vì ƯCLN.BCNN = x.y = abcabc
ta có abcabc= abc.1001. vậy x= 1001, y=abc
mà ƯCLN﴾x,y﴿= abc suy ra BCNN﴾x,y﴿ = 1001
Ta có: ƯCLN(x,y).BCNN(x,y)=x.y
⇒BCNN(x,y)=x.y:ƯCLN(x,y)= abcabc:abc=(abc.1000+abc):abc=abc(1000+1):abc=1001
Vậy BCNN(x,y)=1001
BCNN(x;y) =\(\frac{xy}{UCLN\left(x;y\right)}=\frac{\vec{abcabc}}{\vec{abc}}=1001\)
vì ƯCLN.BCNN = x.y = abcabc
ta có: abcabc= abc.1001. vậy x= 1001, y=abc
NÊn ƯCLN﴾x,y﴿= abc suy ra BCNN﴾x,y﴿ = 1001