(-3x2y3)(2xy)(-1/2x2)
=6x5y4
Bậc là 9
* \(\left(-3x^2y^3\right)\left(2xy\right)\left(\frac{-1}{2}x^2\right)\)
\(=\left[\left(-3\right).2.\left(\frac{-1}{2}\right)\right]\left(x^2.x.x^2\right)\left(y^3.y\right)\)
\(=3.x^5.y^4\)
Bậc : 9
\(\left(-3x^2y^3\right)\left(2xy\right)\left(-\frac{1}{2}x^2\right)\)\(\)
\(=\left[-3\cdot2\cdot\left(-\frac{1}{2}\right)\right]\cdot\left(x^2xx^2\right)\left(y^3y\right)\)
\(=3x^5y^4\)
\(\Rightarrow\)Đơn thức bậc 9 (mình ko chắc chắn lắm)