PTHH: \(NaOH+HCl\rightarrow NaCl+H_2O\)
\(n_{HCl}=\dfrac{m}{M}=\dfrac{18,25}{36,5}=0,5\left(mol\right)\)
\(n_{NaOH}=n_{HCl}=0,5\left(mol\right)\)
\(m_{NaOH}=n.M=0,5.40=20\left(g\right)\)
\(n_{NaCl}=n_{HCl}=0,5\left(mol\right)\)
\(m_{NaCl}=n.M=0,5.58,5=29,25\left(g\right)\)