A(x)+B(x)=2x-3x3+2x2+1+4x3+2x2-5
= x3+4x2+2x-4
thay x=1 vào B(x) ta được
B(x)=4.13+2.13-5
=4+2-5
=1
\(A\left(x\right)+B\left(x\right)=\left(x+2\right)\left(x^2+2x-2\right)\)
thay x=1 \(=>A\left(1\right)+B\left(1\right)=3\left(1+2-2\right)=3\)
Ta có:
A(x)+B(x)=2x-3x³+2x²+1+4x³+2x²-5
=(-3x³+4x³)+(2x²+2x²)+2x+(1-5)
=x³+4x²+2x-4
Thay x=1 vào B(x) ta có:
B(1)=4*1³+2*1²-5
=4+2-5=1