Question

Cho cotα=\(\dfrac{8}{15}\)Tính M=\(\dfrac{sin\alpha+3cos\alpha}{4cos\alpha-3sin\alpha}\)

Answer 1

M=\(\dfrac{sin\alpha+3cos\alpha}{4cos\alpha-3sin\alpha}\)

   = \(\dfrac{1+3cot\alpha}{4cot\alpha-3}\)

   =\(\dfrac{1+\dfrac{8}{5}}{\dfrac{32}{15}-3}\)

   =\(-3\)