a chia 7 dư 3
=> a = 7k + 3
b chia 7 dư 5
=> b = 7t + 5
c chia 7 dư 0
=> c = 7h
a) ( a + b + c ) = ( 7k + 3 + 7t + 5 + 7h ) = 7 . ( k + t + h ) + ( 3 + 5 ) = 7 . ( k + t + h ) + 8 = 7 . ( k + t + h ) + 7 + 1 = 7 . ( k + t + h + 1 ) + 1
vậy ( a + b + c ) chia 7 dư 1