cho xyz la cac so thuc thoa man y+z+1/x=x+z+2/y=x+y+2/z=1/x+y+z tinh gia tri bieu thuc A=2016.x+y^2017+z^2017
a)Cho vi du ve 1 don thuc ,1 da thuc nhung khong phai la don thuc ,2 don thuc dong dang voi nhau ,da thuc 1 bien
b)Hay viet 1 don thuc dong dang voi don thuc don thuc xy\(^3\) sao cho tai x=-1 y=2 gia tri cua don thuc do la so nguyen duong nho hon 10
cho x,y,z la cac so huu ti duong thoa man x+1/yz y +1/xz z+1/xy la cac so nguyen tim gia tri lon nhat cua bieu thuc A=x+y^2+z^3
Cho biểu thức A = x^2+3/x-2
a tim dieu kien cua x de gia tri cua bieu thuc khong xac dinh duoc
b. Voi nhung gia tri nao cua x thi bieu thuc A nhan gia tri la so a
Cho don thuc
A=(2ax2y3)2*(-1/3bx3y)
Xac dinh xem chu nao la hang so , chu nao la bien de don thuc A co bac la
a, 15
b,16
c,10
Help me !!!!!!
cho x,y,z la 3 so thuc tuy y thoa man x+y+z=0 va -1< x<1,-1<y<1,-1<z<1.chung minh rang da thuc x^2+y^4+z^6 co gia tri khong lon hon 2
cho x,y,z la so thuc thoa man y+z+3/x=x+z+2/y=x+y-3/z=1/x+y+z.
Tinh A=2016.x+y^2017+z^2017
cho hai don thuc
A=(2a^3b^2x^4y)(-3/10b^5x^2yz^3)
cac nqn giup minh vs nhe. xac dinh x chu nao la hang.chu nao la bien de don thucA co bac la22
1) A= \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{7}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
b) Cho 3 so x,y,z la 3 so khac 0 thoa man dieu kien :
\(\frac{y+z-x}{x}=\frac{z+x-y}{y}=\frac{x+y-z}{z}\)
Hay tinh gia tri bieu thuc:\(B=\left(1+\frac{x}{y}\right)\left(1+\frac{y}{z}\right)\left(1+\frac{z}{x}\right)\)
