\(x\in\left\{4;-2;2;0\right\}\)
Nhác Giải nha
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x+2/x-1=x-1+2/x-1
Vì x-1 chia hết x-1
=>2 chia hết x-1
=>x-1 thuộc (1,-1,2,-2)
=>x thuôc (2,0,3,-1)
\(B=\frac{x-1+3}{x-1}\)
\(Để:B\in Z\Leftrightarrow\left(x+2\right)⋮\left(x-1\right)\Leftrightarrow\left(x-1\right)+3⋮\left(x-1\right)\)
\(\Leftrightarrow3⋮\left(x-1\right)\Leftrightarrow\left(x-1\right)\inƯ\left(3\right)\Leftrightarrow\left(x-1\right)\in\left(1;-1;3;-3\right)\)
\(\Rightarrow x\in\left\{4;-2;2;0\right\}\)
\(B=\frac{x+2}{x-1}=\frac{x+2-3}{x-1}=1-\frac{3}{x-1}\)
\(\Rightarrow x-1\inƯ\left(3\right)\)
\(Ư\left(3\right)=\left\{\pm1;\pm3\right\}\)
Ta có: x - 3 = -1 => x = 2
x - 3 = 1 => x = 4
x - 3 = -3 => x = 0
x - 3 = 3 => x = 6
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