Question

cho A=\(\frac{196}{197}+\frac{197}{198};B=\frac{196+197}{197+198}.TronghaisốAvàB,sốnàolớnhơn\)

Answer 1

Ta có : A=\(\frac{196}{197}\)+\(\frac{197}{198}\)>\(\frac{196}{198}+\frac{197}{198}\)
              \(\frac{196+197}{198}\)>B=\(\frac{197+197}{197+198}\)
Vậy A>B

Answer 2

Ta có:  B=\(\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

Mà \(\frac{196}{197}>\frac{196}{197+198};\frac{197}{198}>\frac{197}{197+198}=>\frac{196}{197}+\frac{197}{198}>\frac{196}{197+198}+\frac{197}{197+198}\)

=> A>B

Answer 3

a>b nhé t