Ta có: a(b +2001) = ab + 2001a
b(a +2001)=ab + 2001b
vì b >0 nên b + 2001 > 0
Ta có: a(b +2001) = ab + 2001a
b(a +2001)=ab + 2001b
vì b >0 nên b + 2001 > 0
a) Nếu a > b thì ab + 2001a > ab + 2001b
Quảng cáo
⇒a(b+2001)>b(a+2001)⇒ab>a+2001b+2001⇒a(b+2001)>b(a+2001)⇒ab>a+2001b+2001
b) Nếu a < b thì ab + 2001a < ab + 2001b
⇒a(b+2001)<b(a+2001)⇒ab<a+2001b+2001⇒a(b+2001)<b(a+2001)⇒ab<a+2001b+2001
c) Nếu a = b thì ab=a+2001/b+2001