dung rui ban, minh nghi nay h ko ra
Đúng 0
Bình luận (0)
Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Các câu hỏi tương tự
1. Cho a,b,c,d la cac so nguyen thoa man \(a^2=b^2+c^2+d^2\)
chung minh rang a.b.c.d + 2015 viet duoc duoi dang hieu cua 2 so chinh phuong.
2. Cho a,b la cac so duong thoa man dieu kien a+b=1. tim gia tri nho nhat cua bieu thuc
\(P=\frac{2+a}{\sqrt{2-a}}+\frac{2+b}{\sqrt{2-b}}\)
giúp mình với
cho a,b,c >0 thoa man dieu kien a^2 +b^2 +c^2 = 1
tinh gia tri nho nhat cua bieu thuc A= ab/c + bc/a + ca/b
cho a,b,c la do dai 3 canh cua mot tam giac thoa man dieu kien \(\sqrt{a+b-c}+\sqrt{b+c-a}+\sqrt{c+a-b}=\sqrt{a}+\sqrt{b}+\sqrt{c}\)
chung minh a,b,c la 3 canh cua mot tam giac deu
cho a,b,c la ba so thuc duong thoa man dieu kien a+b+c=1
chung minh rang P=\(\sqrt{\frac{ab}{c+ab}}+\sqrt{\frac{bc}{a+bc}}+\sqrt{\frac{ca}{b+ca}}\le\frac{3}{2}\)
Cho a,b,c la cac so duong thoa man dieu kien \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=1\)
Cmr \(\frac{a^2}{a+bc}+\frac{b^2}{b+ca}+\frac{c^2}{c+ab}\ge\frac{a+b+c}{4}\)
Cho a,b,c la cac so duong thoa man dieu kien \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=1\)
Cmr \(\frac{a^2}{a+bc}+\frac{b^2}{b+ca}+\frac{c^2}{c+ab}\ge\frac{a+b+c}{4}\)
Choa,b,c la cac so duong thoa man dieu kien \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=1\)
Cmr \(\frac{a^2}{a+bc}+\frac{b^2}{b+ca}+\frac{c^2}{c+ab}\ge\frac{a+b+c}{4}\)
Cho a,b,c la cac so duong thay doi thoa man dieu kien : 5a2+2abc+4b2+3c2 =60
Tim MAX A=a+b+c
cho 3 so duong a,b,c thoa man a+b+c=1/abc chung minh rang can ((1+b^2c^2)(1+a^2c^2)/c^2+a^2b^2c^2)=a+b