\(a=7+\left(7^2+7^4\right)+\left(7^3+7^5\right)+...\left(7^{2017}+7^{2019}\right)\)
\(a=7+7^2.\left(1+7^2\right)+7^3.\left(1+7^2\right)+...+7^{2017}.\left(1+7^2\right)\)
\(a=7+7^2.50+7^3.50+...+7^{2017}.50\)
\(a=7+50.\left(7^2+7^3+...+7^{2017}\right)\)
\(7⋮̸50,50.\left(7^2+7^3+...+7^{2017}\right)⋮50=>a⋮̸50\)