Các câu hỏi tương tự
cho A=1/1.2+1/3.4+1/5.6+...+1/99.100. chứng minh rằng :7/12 <A<5/16
Cho A= 1\1.2 + 1\3.4 + 1\5.6 + ... + 1\99.100
Chứng minh rằng: 7\12 < A < 5\6
CHỨNG MINH 7/12<A<5/6 với A=1/1.2+1/3.4+1/5.6+.....+1/99.100
Cho A = 1/1.2+1/3.4+1/5.6+...+1/99.100
a Chứng minh A= 1/51+1/52+1/53+...+1/100
b Chứng minh 7/12<A<5/6
Cho A = (1/1.2 + 1/3.4 + 1/5.6 +...+ 1/67.68).35.36...67.67
Chung minh rang A chi ahet cho 103
chung to rang
1/1.2 cong 1/2.3 cong 1/3.4 cong ... cong 1/99.100 be hon 1
\(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}.\)
CM. \(\frac{5}{6}< A< \frac{7}{12}\)
cho A = \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.......+\frac{1}{99.100}\)
CMR: \(̃̃̃̃\frac{7}{12}< A< \frac{5}{6}\)
cho A= \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.........+\frac{1}{99.100}\)