A = 0.01 + 0.02 + 0.03 +... + 0.98 + 0.99
=> 100A = 1+2+3+...+98+99
=>100A = \(\frac{100.99}{2}\)=4950
=> 2A = 4950 : 50 = 99
Vậy 2A = 99
\(A=0,01+0,02+0,03+...+0,98+0,99\)
\(\Rightarrow100A=1+2+4+...+98+99\)
\(\Rightarrow100A=\frac{\left(99+1\right)99}{2}=4950\)
\(\Rightarrow2A=4950\div50=99\)