Cho \(a,b,c>0.\)\(Cmr:\frac{a^4}{\left(a+b\right)\left(a^2+b^2\right)}+\frac{b^4}{\left(b+c\right)\left(b^2+c^2\right)}+\frac{c^4}{\left(c+a\right)\left(c^2+a^2\right)}\ge\frac{a+b+c}{4}\)
Cho a+b+c=0 CMR
\(a^5.\left(b^2+c^2\right)+b^5.\left(c^2+a^2\right)+c^5.\left(a^2+b^2\right)=\frac{1}{2}.\left(a^3+b^3+c^3\right).\left(a^4+b^4+c^4\right)\)
Giải hộ t bài này (đáng tiếc thầy giáo k cho dùng cauchy ức chế vãi linh hồn, đừng ai dùng cauchy nhé)
Cho a,b,c > 0. CMR
\(\frac{a^4}{\left(a+b\right)\left(a^2+b^2\right)}+\frac{b^4}{\left(b+c\right)\left(b^2+c^2\right)}+\frac{c^4}{\left(c+a\right)\left(c^2+a^2\right)}\ge\frac{a+b+c}{4}\)
Cho\(\hept{\begin{cases}a,b,c>0\\abc>1\end{cases}CMR:}2\left(a^2+b^2+c^2\right)+4\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\ge7\left(a+b+c\right)-3\)
Cho \(a,b,c>0\)
CMR :\(\frac{a^4}{b\left(b+c\right)}+\frac{b^4}{c\left(c+a\right)}+\frac{c^4}{a\left(a+b\right)}\ge\frac{1}{2}\left(ab+bc+ca\right)\)
Áp dụng bđt Svac-xo ta có :
\(VT\ge\frac{\left(a^2+b^2+c^2\right)^2}{a^2+b^2+c^2+ab+bc+ca}\ge\frac{\left(a^2+b^2+c^2\right)^2}{2\left(a^2+b^2+c^2\right)}=\frac{a^2+b^2+c^2}{2}\ge\frac{ab+bc+ca}{2}\)
Dấu "-" xảy ra \(< =>a=b=c\)
Cho a,b,c>0. CMR
\(\frac{a^3}{\left(b+c\right)^2}+\frac{b^3}{\left(c+a\right)^2}+\frac{c^3}{\left(a+b\right)^2}\ge\frac{a+b+c}{4}\)
cho a,b,c > 0 thỏa mãn abc = 1. CMR :
\(2\left(a^2+b^2+c^2\right)+4\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\ge7\left(a+b+c\right)-3\)
bài tập NC hè
cho \(a,b,c>0.\)\(Cmr:\left(\frac{a}{a+b}\right)^2+\left(\frac{b}{b+c}\right)^2+\left(\frac{c}{c+a}\right)^2\ge\frac{3}{4}\)
1)cho a + b + c = 0 CMR
\(\left(a^2+b^2+c^2\right)^2=2\left(a^4+b^4+c^4\right)\)
