A = 21 + 22 + 23 + ... + 290
=> A = ( 21 + 22 + 23 ) + ... + ( 288 + 289 + 290 )
=> A = 2. ( 1 + 2 + 22 ) + ... + 288.( 1 + 2 + 22 )
=> A = 2 . 7 + ... + 288 . 7
=> A = ( 2 + ... + 288 ) . 7 \(⋮\)7
\(\Rightarrow A⋮7\)
A = 2 + 22 + 23 + ... + 290
A = ( 2 + 22 + 23 ) +... + ( 288 + 289 + 290 )
A = 2 . ( 1 + 2 + 4 ) + ... + 288 . ( 1 + 2 + 4 )
A = 2 . 7 + .. + 288 . 7
A = ( 2 + .. + 288 ) . 7 \(⋮\)7
Vậy A \(⋮\)7