\(n_{H_2SO_4.2SO_3}=\dfrac{38,7}{258}=0,15\left(mol\right)\)
⇒ BTNT S: nH2SO4 (thêm vào) = 0,15.3 = 0,45 (mol)
\(m_{H_2SO_4\left(30\%\right)}=\dfrac{100.30\%}{98}=30\left(g\right)\)
\(\Rightarrow C\%_{H_2SO_4}=\dfrac{0,45.98+30}{38,7+100}.100\%\approx53,42\%\)