a, \(m_{Cl2,O2}=96,9-35,1=61,8\left(g\right)\)
Gọi \(n_{Cl2}=a\left(mol\right);n_{O2}=b\left(mol\right)\)
\(n_{Cl2,O2}=\frac{26,88}{22,4}=1,2\left(mol\right)\)
Ta có hệ phương trình:
\(\left\{{}\begin{matrix}71a+36b=61,8\\a+b=1,2\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}a=0,6\\b=0,6\end{matrix}\right.\left(mol\right)\)
\(\rightarrow\%V_{Cl2}=\%V_{O2}=50\%\)
b, Quá trình nhường e
\(Mg^o\rightarrow Mg^{+2}+2e\)
x______________2x
\(Al^o\rightarrow Al^{+3}+3e\)
y_____________3y
\(\rightarrow24x+27y=35,1\left(1\right)\)
Quá trình nhận e
\(Cl_2^o+2e\rightarrow2Cl^{-1}\)
0,6___1,2_______
\(O_2^o+4e\rightarrow2O^{-2}\)
0,6__2,4__________
\(\rightarrow2x+3y=3,6\left(2\right)\)
Từ ( 1 ) và ( 2 ) \(\rightarrow\left\{{}\begin{matrix}x=0,45\\y=0,9\end{matrix}\right.\)
\(\rightarrow m_{Mg}=0,45.24=0,8\left(g\right)\)
\(\rightarrow\%m_{Mg}=\frac{10,8}{35,1}.100\%=30,8\%\)
\(\rightarrow\%_{Al}=100\%-30,8\%=69,2\%\)