Ta có:
\(n_{MnO2}=\frac{34,8}{87}=0,4\left(mol\right)\)
\(n_{HCl}=\frac{36,5.200}{100.36,5}=2\left(mol\right)\)
\(PTHH:MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
_________0,4______1,6______0,4_______0,4____
\(\Rightarrow n_{HCl\left(tt\right)}=\frac{80.0,4}{100}=0,32\left(mol\right)\)
\(\Rightarrow V_{Cl2}=0,32.22,4=7,168\left(l\right)\)
\(n_{NaOH}=0,5.2=1\left(mol\right)\)
\(\frac{n_{Cl2}}{1}>\frac{n_{NaOH}}{2}\Rightarrow\) NaOH dư
\(Cl_2+2NaOH\rightarrow NaCl+NaClO+H_2O\)
0,32____0,64 _____0,32_____0,32 ______
\(n_{NaOH\left(dư\right)}=1-0,64=0,36\left(mol\right)\)
Vdd sau pư = 500ml = 0,5l
\(\Rightarrow\left\{{}\begin{matrix}CM_{NaCl}=CM_{NaClO}=\frac{0,32}{0,5}=0,64M\\CM_{NaOH\left(dư\right)}=\frac{0,36}{0,5}=0,72M\end{matrix}\right.\)