\(n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right)\\ a,PTHH:2Al+6HCl\rightarrow2AlCl_3+3H_2\\ n_{HCl}=\dfrac{6}{2}.0,1=0,3\left(mol\right)\\ b,V=V_{ddHCl}=\dfrac{0,3}{3}=0,1\left(l\right)=100\left(ml\right)\)
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