\(a,V_X=2,24\left(l\right)\\ V_{N_2}=\dfrac{2.2,24}{2+3}=0,896\left(l\right)\\ V_{O_2}=\dfrac{3.2,24}{2+3}=1,344\left(l\right)\\ b,n_{N_2}=\dfrac{0,896}{22,4}=0,04\left(mol\right)\\ n_{O_2}=\dfrac{1,344}{22,4}=0,06\left(mol\right)\\ c,m_X=m_{N_2}+m_{O_2}=28.0,04+0,06.32=3,04\left(g\right)\)