\(D=0,8g\)/cm3
Trong 200ml rượu etylic \(11,5^o\) có:
\(V_{C_2H_5OH}=V_{dd}\cdot\dfrac{11,5}{100}=200\cdot\dfrac{11,5}{100}=23ml\)
\(\Rightarrow m_{C_2H_5OH}=D\cdot V=23\cdot0,8=18,4g\)
\(C_2H_5OH+O_2\rightarrow CH_3COOH+H_2O\)
46 60 (gam)
18,4 m (gam)
\(\Rightarrow m=24g\)
\(m_{ddCH_3COOH}=\dfrac{24}{15\%}\cdot100\%=160g\)