Ta có: \(n_{\left(CH_3COO\right)_2Zn}=\dfrac{10,98}{183}=0,06\left(mol\right)\)
PT: \(2CH_3COOH+Zn\rightarrow\left(CH_3COO\right)_2Zn+H_2\)
__________0,12____0,06__________0,06_____0,06 (mol)
a, \(m_{Zn}=0,06.65=3,9\left(g\right)\)
b, \(V_{H_2}=0,06.22,4=1,344\left(l\right)\)
c, \(C\%_{CH_3COOH}=\dfrac{0,12.60}{200}.100\%=3,6\%\)