Ta có: ∠\(xOy\) + ∠\(yOz\) = ∠\(xOz\) ( kề bù )
\(124^o\) + ∠\(yOz\) = \(180^o\)
∠\(yOz\) = \(180^o-124^o\)
∠\(yOz\) = \(56^o\)
Giải:
Vì \(x\widehat{O}y\) và \(y\widehat{O}z\) là 2 góc kề bù
\(\Rightarrow x\widehat{O}y+y\widehat{O}z=180^o\)
\(124^o+y\widehat{O}z=180^o\)
\(y\widehat{O}z=180^o-124^o\)
\(y\widehat{O}z=56^o\)