\(S=\dfrac{2mu2}{1.2}+\dfrac{2mu2}{2.3}+\dfrac{2mu2}{3.4}+...+\dfrac{2mu2}{2022.2023}\)
(mu = mũ)
cho s = 1+2+2mu2+...+2mu2018 tính s
S=2+2mu2+2mu3+....+2mu100;hay chung to rang S chia het cho 15 va chu so tan cung cua S
Cho S =1+2+2mu2+2mu3+...+2mu9+2mu10+2mu11.Hay so sanh Svoi 5*2mu10
tinh S=1mu2+2mu2+.....+10mu2
tinh S=1/2+1/2mu2+1/2mu3+...+1/2mu20
S=1/2mu2 + 1/3mu2 + 1/4mu2 + ... + 1/100mu2 bé hơn 1
Cho b=1+2+2mu2+2mu3+...+2mu6,A=2mu2+2mu3+2mu4+..+2mutam chứng minh rằng A=4B
11/2mu2+1/3mu2+1/4mu2+...+1/9mu2 cmr 2/5<s<8/9
