Đáp án B
R-NH2 + HCl → R-NH3Cl
BTKL: m H C l = m m u ố i – m a m i n = 0,876 (g) → n H C l = 0,024 mol
→ n X = 0,024 → M X = 73 → C4H9NH2.
Đồng phân: C-C-C-C-N; C-C-C(N)-C; C-C-C(C)-N; C-C(C)-C-N; C-C-C-N-C; C-C(C)-C-C; C-C-N-C-C; C-N(C)-C-C.
Đáp án B
R-NH2 + HCl → R-NH3Cl
BTKL: m H C l = m m u ố i – m a m i n = 0,876 (g) → n H C l = 0,024 mol
→ n X = 0,024 → M X = 73 → C4H9NH2.
Đồng phân: C-C-C-C-N; C-C-C(N)-C; C-C-C(C)-N; C-C(C)-C-N; C-C-C-N-C; C-C(C)-C-C; C-C-N-C-C; C-N(C)-C-C.