a.\(Ca+2H_2O\rightarrow^{t^0}Ca\left(OH\right)_2+H_2\uparrow\)
\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
b.\(n_{H_2\left(đktc\right)}=\dfrac{V}{22,4}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
\(Ca+2H_2O\rightarrow^{t^0}Ca\left(OH\right)_2+H_2\uparrow\).
0,15 : 0,15 (mol)
\(m_{Ca}=n.M=0,15.40=6\left(g\right)\)
\(m_{CaO}=m_{hh}-m_{Ca}=17,2-6=11,2\left(g\right)\)