Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Ta có: \(\left(x-y\right)\left(x+y\right)=\left(x^2-y^2\right)\)
\(\Rightarrow\left(7a-3b+2c\right)\left(7a-3b-2c\right)=\left(7a-3b\right)^2-\left(2c\right)^2\)
\(=49a^2-42ab+9b^2-4c^2\)
\(=49a^2-42ab+9b^2-4\left(10a^2-10b^2\right)\)
\(=9a^2-2.3.7ab+49b^2=\left(3a-7b\right)^2\left(ĐPCM\right)\)
Cho 10a^2 = 10b^2 + c^2
CMR: ( 7a - 3b + 2c )( 7a - 3b - 2c ) - (3a - 7b )^2
Cho 10a^2 = 10b^2 + c^2
CMR: ( 7a - 3b + 2c )( 7a - 3b - 2c ) - (3a - 7b )^2
cho: 10a^2=10b^2+c
tinh (7a-3b+2c).(7a-3b-2c)=(3a-7b)^2
Cho 10a^2=10b^2+c^2. Chứng minh rằng (7a-3b+2c)(7a-3b-2c)=(3a-7b)^2
Cho 10a^2=10b^2+c^2. Chứng minh rằng (7a-3b+2c)(7a-3b-2c)=(3a+b)^2
cho \(10a^2\)=\(10b^2\)+ \(c^2\)
chứng minh rằng : (7a - 3ab + 2c ) (7a - 3b - 2c ) = (3a - 7b )\(^2\)
cmr: (a+2b-3c)^3+(b+2c-3a)^3+(c+2a-3b)^3=3.(a+2b-3c).(b+2c-3a).(c+2a-3b)
1) Rút gọn :
\(B=\frac{\left(a+2b\right)^3-\left(a-2b\right)^3}{\left(2a+b\right)^3-\left(2a-b\right)^3}:\frac{3a^4+7a^2b^2+3b^4}{4a^4+7a^2b^2+3b^4}\)
Cho a+b+c = 1 và 3a+2b>c, 3b+2c>a, 3c+2a>b. Chứng minh: 1/(3a+2b-c) + 1/(3b+2c-a) + 1/(3c+2a-b) >hoặc = 9/4