C=\(\frac{6^6+6^3\cdot3^3+3^6}{-73}\)
C=\(\frac{53217}{-73}\)
C= -729
ta co\(\frac{6^6+6^3.3^3+3^6}{-73}\)=\(\frac{2^6.3^6+2^3.3^3.3^3+3^6}{-73}\)=\(\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)=\(\frac{3^6.73}{-73}\)= \(-\left(3^6\right)\)
C=\(\frac{6^6+6^3\cdot3^3+3^6}{-73}\)
C=\(\frac{53217}{-73}\)
C= -729
ta co\(\frac{6^6+6^3.3^3+3^6}{-73}\)=\(\frac{2^6.3^6+2^3.3^3.3^3+3^6}{-73}\)=\(\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)=\(\frac{3^6.73}{-73}\)= \(-\left(3^6\right)\)
\(\frac{6^6+6^3\cdot3^3+3^6}{-73}-\frac{45^{10}\cdot5^{20}}{75^{15}}\)
Giúp mình với !
N = \(\frac{6^6+6^3.3^3+3^6}{-73}\)
GIÚP MÌNH NHÉ!
Bài 1 .\(A=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^{9\cdot14^3}}\)
Bài 2 .\(\frac{37-x}{x+13}=\frac{3}{7}\)
Bài 3 . \(x=\frac{y}{2}=\frac{z}{3}và4x-3y+2z=36\)
Bài 4 . \(x:y:z=3:4:5và2x^2+2y^2-3z^2=-100\)AI LÀM ĐƯỢC THÌ GIÚP MÌNH VỚI NHA!
\(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
giúp mk zới nhá vế sau mk chịu òi
\(\frac{2^{12}\cdot3^5-4^6\cdot3^6}{2^{12}\cdot9^3+8^4\cdot3^3}\)
RÚT GỌN
a/\(\frac{9^4\cdot27^5\cdot3^6\cdot3^4}{3^8\cdot81^4\cdot234\cdot8^6}\)
b/\(N=\frac{4^6\cdot9^5+6^6\cdot120}{8^4-3^{12}-6}\)
Tính:
a/\(\frac{3^{17}\cdot81^{11}}{27^{10}\cdot9^{15}}\)
b/\(\frac{9^2\cdot2^{11}}{16^2\cdot6^3}\)
c/\(\frac{2^{10}\cdot3^{31}+2^{40}\cdot3^6}{2^{11}\cdot3^{31}+2^{41}\cdot3^6}\)
\(B=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{56^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
\(TínhA=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)