`x/(-4) = (-11)/2`
`=> 2x=-4.(-11)`
`=> 2x=44`
`=>x=44:2`
`=>x=22`
`---`
`(15-x)/(x+9) =3/5`
`=> (15-x).5=(x+9).3`
`=> 75-5x =3x+27`
`=> -5x -3x=27 -75`
`=> -8x=-48`
`=>x=-48:(-8)`
`=>x=6`
a) x−4=−112
x=(−11).(−4)2
x=22.
b) 15−xx+9 =35
(15−x).5 =(x+9).3
75−5x =3x+27
8x=48
x=6.
a)\(x=[\left(-4\right)\times\left(-11\right)]\div2=22\)
b)\(\dfrac{15-12}{\left(-4\right)+9}=\dfrac{3}{5}\)
\(\dfrac{x}{-4}\) = \(\dfrac{-11}{2}\) => x.2 = (-4) . (-11) = (-4).(-11) : 2= 22
a) x=(-11).(-4):2=22
b)\(\dfrac{x}{x}\)=\(\dfrac{15-3}{5+9}\)=\(\dfrac{12}{14}\)=\(\dfrac{6}{7}\)
a)x/-4=-11/2
--->x.2=-4.(-11)
x.2=44
x =44:2
x = 22
(-11).(-4)=x.2
44=x.2
x=44:2
x=11
Vậy x=11
a, \(\dfrac{-11.\left(-4\right)}{2}\)= 22
b, 3.(x + 9) = 5.(15 - x)
a) x = -4.-11/2
x = 22
b) (15 - x ).5 = ( x + 9 ).3
75 - 5x = x3 + 27
8x = 48
x = 6