(x-3)2012+(3y-12)2014<(=)0
(x-3)2012;(3y-12)2014>(=)0
mà (x-3)2012+(3y-12)2014<(=)0
=>(x-3)2012=(3y-12)2014=0
=>x-3=3y-12=0
=>x=3;y=4
Vậy x=3;y=4
(x-3)2012+(3y-12)2014<(=)0
(x-3)2012;(3y-12)2014>(=)0
mà (x-3)2012+(3y-12)2014<(=)0
=>(x-3)2012=(3y-12)2014=0
=>x-3=3y-12=0
=>x=3;y=4
Vậy x=3;y=4
cặp (x;y) thỏa mãn: (x-3)^2012) + (3y-12)^2014) < hoặc = 0 x trước y sau
Cặp ( x;y ) thỏa mãn ( x - 3 )^2012 + (3y - 12)^2014 < 0
Cặp x,y thỏa mãn:(x-3)2012+(3y-12)2014 bé hơn hoặc =0 là x,y=(.....;..........)
1) (3x-5/9) mu 200 + (3y+0,4/3) mu 2008 =0
tim cap x;y thoa man
2) (2x-1) mu 2k + (y-(1/3))mu 4k = 0
ai truoc thi mk like
Cau 1; cho\(\frac{x}{2}=\frac{y}{5}\)vaxy=90. So cap (x;y) thoa man la
Cau 2 : Cho a+d=b+c va \(a^2+d^2=b^2+c^2\)(b,d khac 0).Khi do 4 so lap thanh ti le thuc nao
Cau 3 :GTLN cua phan so \(\frac{7n-8}{2n-3}\)
Cau 4: Cho A=\(\frac{12}{x-15}\) dieu kien de 0<A<1 va A>1
Cau 5 ; tim x biet /-x-5//x=5=10
Cau 6: tap hop cac so nguyen cua x thoa man (3x^2-51)^2014=(-24)^2014
Cau 7: tap hop cac so thoa man /x-y/+/y+9/25/=0
Cặp (x,y) thỏa mãn:
(x-3)2012+(3y-12)2014 <=0
tim tat ca cac cap so nguyen x,y thoa man 2^x+1.3^y=12^x
cặp x,y thỏa mãn (x-3)2012 + (3y-12)2014 < 0 là ?
Cặp (x,y) thỏa mãn:
(x-3)2012+(3y-12)2014 <=0