\(\sqrt{2x^2-4x+5}=x-4\left(x\ge4\right)\)
\(\Rightarrow2x^2-4x+5=x^2-8x+16\)
\(\Rightarrow x^2+4x-11=0\)
Có: \(\Delta=4^2-4\left(-11\right)=60>0\Rightarrow\sqrt{\Delta}=2\sqrt{15}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-4+2\sqrt{15}}{2}=-2+\sqrt{15}\left(l\right)\\x=\frac{-4-2\sqrt{15}}{2}=-2-\sqrt{15}\left(l\right)\end{cases}}\)
Vậy \(x\in\left\{\phi\right\}\)
gia tri lon nhat cua bieu thuc P=can bac hai cua (3+2x-x^2)
Can bậc hai cua (x-1)(x-3)
B,can bac hai cua 4/ x+3
Cho cac so duong x, y,z thoa man x+y+z=3. Tim GTLN cua P= can bac hai cua (x+y) + can bac hai cua (y+z) + can bac hai cu(x+z)
Giáp Phuong Trinh 3(x2+x+1)=(x+can bac hai cua x-1)2
3(x^2-1) +4x=4xsqrt(4x-3)
16x^4+5 =6can bâc ba 4x^3+x
cănbậc ba cua x^2 +4 + sqrt( x+7) =2sqrt(2x)
GTLN 4- can cua x^2-4x+4
BAI 1 TINH GIA TRI CUA BTHUC
A=3PHAN 1+CAN 3 -2PHAN 1-CAN 3
B=CAN 10-CAN 5 PHAN CAN 2-1 -3CAN 5 +5PHAN CAN 5+3 +2 PHAN CAN 2
BAI 2 GIAI PT
a)CAN 49-28X+4X MU 2 -5=0
b)1PHAN 2 CAN X-2 -4 CAN 4X -8 PHAN 9 +CAN 9X+18 -5=0
MOI NGUOI GIUP MINH VS MINH CAN LUON BAY GIO
CAM ON
can bac hai cua 100006842400097
can bac hai cua 21cong6can 6