TN

c1

a, x/15 + 7/20= 73/60

b, x+1/3 = 12/20

c, 11/8 + 13/6 = 85/x

c2

a, 60%.x + 2/3 .x = -76

b, -5/6 - x = 7/12+ -1/3

c, x -4 = -14/35 : 7/5

d, ( 2/7.x + 3/7 ) : 11/5 - 3/7 =1

 

H24
26 tháng 4 lúc 20:06

Câu 1:

\(a,\dfrac{x}{15}+\dfrac{7}{20}=\dfrac{73}{60}\)

\(\Rightarrow\dfrac{x}{15}=\dfrac{73}{60}-\dfrac{7}{20}\)

\(\Rightarrow\dfrac{x}{15}=\dfrac{13}{15}\)

\(\Rightarrow x=13\)

b, \(x+\dfrac{1}{3}=\dfrac{12}{20}\)

\(\Rightarrow x=\dfrac{3}{5}-\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{4}{15}\)

c, \(\dfrac{11}{8}+\dfrac{13}{6}=\dfrac{85}{x}\)

\(\Rightarrow\dfrac{85}{24}=\dfrac{85}{x}\)

\(\Rightarrow x=24\)

Câu 2:

a, \(60\%\cdot x+\dfrac{2}{3}\cdot x=-76\)

\(\Rightarrow x\cdot\left(60\%+\dfrac{2}{3}\right)=-76\)

\(\Rightarrow x\cdot\dfrac{19}{15}=-76\)

\(\Rightarrow x=-76:\dfrac{19}{15}\)

\(\Rightarrow x=-60\)

b, \(-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

\(\Rightarrow-\dfrac{5}{6}-x=\dfrac{1}{4}\)

\(\Rightarrow x=-\dfrac{5}{6}-\dfrac{1}{4}\)

\(\Rightarrow x=-\dfrac{13}{12}\)

c, \(x-4=\dfrac{-14}{35}:\dfrac{7}{5}\)

\(\Rightarrow x-4=\dfrac{-2}{5}\cdot\dfrac{5}{7}\)

\(\Rightarrow x-4=-\dfrac{2}{7}\)

\(\Rightarrow x=-\dfrac{2}{7}+4\)

\(\Rightarrow x=\dfrac{26}{7}\)

d, \(\left(\dfrac{2}{7}\cdot x+\dfrac{3}{7}\right):\dfrac{11}{5}-\dfrac{3}{7}=1\)

\(\Rightarrow\left(\dfrac{2}{7}\cdot x+\dfrac{3}{7}\right)\cdot\dfrac{5}{11}=1+\dfrac{3}{7}\)

\(\Rightarrow\dfrac{2}{7}\cdot x\cdot\dfrac{5}{11}+\dfrac{3}{7}\cdot\dfrac{5}{11}=\dfrac{10}{7}\)

\(\Rightarrow\dfrac{10}{77}\cdot x+\dfrac{15}{77}=\dfrac{10}{7}\)

\(\Rightarrow\dfrac{10}{77}\cdot x=\dfrac{110}{77}-\dfrac{15}{77}\)

\(\Rightarrow\dfrac{10x}{77}=\dfrac{95}{77}\)

\(\Rightarrow10x=95\)

\(\Rightarrow x=95:10\)

\(\Rightarrow x=\dfrac{19}{2}\)

$\text{#}Toru$

Bình luận (1)
H24
26 tháng 4 lúc 20:28

`1a)x/15+7/20=73/60`

`=>x/15=73/60-7/20`

`=>x/15=13/15`

`=>x=13`

Vậy `x=13`

_

`b)x+1/3=12/20`

`=>x=12/20-1/3`

`=>x=4/5`

Vậy `x=4/5`

_

`c)11/8+13/6=85/x`

`=>85/24=85/x`

`=>x=24`

Vậy `x=24`

_

`2a)60%x+2/3x=-7/6`

`=>3/5x+2/3x=-7/6`

`=>19/15x=-7/6`

`=>x=-7/6:19/15`

`=>x=-105/114`

Vậy `x=-105/114`

_

`b)-5/6-x=7/12+(-1/3)`

`=>-5/6-x=1/4`

`=>x=-5/6-1/4`

`=>x=-13/12`

Vậy `x=-13/12`

_

`c)x-4=-14/35:7/5`

`=>x-4=-2/7`

`=>x=-2/7+4`

`=>x=26/7`

Vậy `x=26/7`

_

`d)(2/7x+3/7):11/5-3/7=1`

`=>(2/7x+3/7):11/5=3/7`

`=>2/7x+3/7=3/7 . 11/5`

`=>2/7x=3/7 . 11/5-3/7`

`=>2/7x=3/7(11/5-1)`

`=>2/7x=3/7 . 6/5`

`=>2/7x=18/35`

`=>x=18/35:2/7`

`=>x=9/5`

Bình luận (1)

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