\(\rightarrow\left(\dfrac{1}{4}\right)^{4x}:\left(\dfrac{1}{4}\right)^{2x}=\left(\dfrac{1}{64}\right)^2=\left(\dfrac{1}{4}\right)^6\\ \rightarrow\left(\dfrac{1}{4}\right)^{4x-2x}=\left(\dfrac{1}{4}\right)^6\\ \rightarrow4x-2x=6\\ 2x=6\\ \rightarrow x=3\)
Tìm x, biêt:
(1/8+1/16+1/32+1/64+1/128+1/256)*x=1/512
giúp mk nha
Thực hiện các phép tính
B,
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256
C,
1/1x2 + 1/2x3 + 1/3x4 + ........ + 1/99x100
D,
( 1-1/2 ) x ( 1- 1/3 ) x ( 1-1/4 ) x ....... x ( 1- 1/100 )
bài 1 : 1/1x2+1/2x3+1/3x4+1/5x6+1/6x7
Bài 2:1/2+1/6+1/12+1/30+1/42+1/56+1/72
Bài 3: (1-1/2)x(1-1/3)x....x(1-2019)
Bài 4:1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512
1/2-1/4+1/8-1/16+1/32-1/64+1/128-1/256<1/3
Tính:
\(\frac{\frac{1}{3}+\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}+\frac{4}{14}-\frac{2}{13}}\) x \(\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{256}}{1-\frac{1}{4}+\frac{1}{16}-\frac{1}{64}}\) + \(\frac{5}{8}\)
GIÚP MÌNH VỚI. MÌNH CẦN GẤP!
Chứng mình rằng:A=1/2+1/16+1/36+1/64+1/100+1/144+1/196+1/256+1/324<1/2
Chứng minh rằng:A=(1/4)+(1/16)+(1/64)+(1/100)+(1/144)+(1/196)+(1/256)+(1/324)<1/2
Chứng minh rằng A = 1/4+1/16+1/36+1/64+1/100+1/144+1/196+1/256+1324 < 1/2
Chứng minh:1/2-1/4+1/8-1/16+1/32-1/64+1/128-1/256+1/512-1/1024<1/3
Tính nhanh :
256 - 128 - 64 - 36 - 16 - 8 - 4 - 2 - 1
