\(sin^2a+cos^2a=1\)
\(\Rightarrow cos^2a=1-\left(\frac{5}{13}\right)^2\)
\(\Rightarrow cos^2a=\frac{144}{169}\)
\(\Rightarrow cosa=\sqrt{\frac{144}{169}}=\frac{12}{16}\)
Ta có : \(cotga=\frac{cosa}{sina}=\frac{5}{13}:\frac{12}{16}=\frac{12}{5}\)
\(tana.cotga=1\)
\(\Rightarrow tan\alpha=1:\frac{12}{5}\)
\(\Rightarrow tan\alpha=\frac{5}{12}\)
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