\(x=2y\Rightarrow\frac{2x+y}{x-y}=\frac{4y+y}{2y-y}=\frac{5y}{y}=5\)
x/y=2
=> x=2y
=> \(\frac{2x+y}{x-y}=\frac{2.2y+y}{2y-y}=\frac{4y+y}{y}=\frac{5y}{y}=5\)
Ta có: \(\frac{x}{y}=2\Rightarrow x=2y\)
Ta có:
\(\frac{2x+y}{x-y}=\frac{2\left(2y\right)+y}{2y-y}=\frac{4y+y}{y}=\frac{5y}{y}=5\)
Tick nha